Chapter 3: STOICHIOMETRY

 

       Chapter 3:Stoichiometry

 Key Skills:

 •Balance chemical equations 
•Predict the products of simple aggregate, decomposition, and combustion reactions. •Calculate method weights 
•Convert grams to moles and moles to grams using molar masses. 
•Convert number of molecules to moles and moles to quantity of molecules the usage of Avogadro’s wide variety 
•Calculate the empirical and molecular formulation of a compound from percentage composition and molecular weight. 
•Identify restricting reactants and calculate amounts, in grams or moles, or reactants fed on and merchandise shaped for a reaction.
 •Calculate the percent yield of a reaction.











 Stoichiometry is the study at of the quantitative relationships in materials and their reactions 
 –Chemical equations 
–The mole and molar mass 
 –Chemical formulas 
 –Mass relationships in equations 
Chapter 3: STOICHIOMETRY

 –Limiting reactant 














 Definitions
Reactants are the materials ate up
Products are the substances fashioned
Coefficients are numbers earlier than the 
components of a substance in an equation
• A balanced equation has the identical 
quantity of atoms of every detail on both 
facets of the equation







          Chemical Equations

• A chemical equation is a shorthand notation to 
describe a chemical reaction
– Just like a chemical components, a chemical equation 
expresses quantitative members of the family 
• Subscripts tell the quantity of atoms of every detail in a 
molecule
• Coefficients tell the wide variety of molecules
Chapter 3: STOICHIOMETRY









Coefficients vs. subscripts
Chapter 3: STOICHIOMETRY

Hydrogen and oxygen can make water or hydrogen peroxide
2 H2(g) + O2(g) → 2 H2O(l)
H2(g) + O2(g) → H2O2(l)

Chapter 3: STOICHIOMETRY








Anatomy of a Chemical Equation



Chapter 3: STOICHIOMETRY




Writing Balanced Equations
• Write the appropriate method for every 
substance
H2 + Cl2  HCl
• Add coefficients so the variety of atoms 
of each element are the equal on each 
aspects of the equation
H2 + Cl2  2HCl







Balancing chemical equations 

• Assume one molecule of the most complicated 
substance
C5H12 + O2  CO2 + H2O
• Adjust the coefficient of CO2
to stability C
C5H12 + O2  5CO2 + H2O
• Adjust the coefficient of H2O to stability H
C5H12 + O2  5CO2 + 6H2O
• Adjust the coefficient of O2
to stability O
C5H12 + 8O2  5CO2 + 6H2O
• Check the balance with the aid of counting the quantity of 
atoms of every detail.




Balancing Equations
• Sometimes fractional coefficients are 
obtained
C5H10 + O2  CO2 + H2O
C5H10 + O2  5 CO2 + H2O
C5H10 + O2  five CO2 + five H2O
C5H10 + (15/2) O2  5 CO2 + 5 H2O
• Multiply all coefficients through the 
denominator
2 C5H10 + 15 O2  10 CO2 + 10 H2O


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